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  1. 11-29-2015, 02:35 PM Top | #1
    Aug 2013
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  3. 11-29-2015, 03:41 PM Top | #2
    Dec 2013
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    ...


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  5. 11-29-2015, 10:16 PM Top | #3
    Feb 2014
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    f(z)=(z-i sqrt 2)(z^2+z+74)

    z=i sqrt 2 or z =(-1+sqrt 295 i) /2 or z=(-1-sqrt 295 i)/2

    so the equation has one pure imaginary solution

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     (11-30-2015),  (11-30-2015),  (11-29-2015)
  7. 11-30-2015, 01:52 AM Top | #4
    Aug 2013
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    Thanked: 2484

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    . . .


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