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01-14-2012, 10:48 PM
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#1
/ sin〖31〗
Solution:-
Let f(x)=sinx
f^- (x)=cosx
b=〖31〗^= 31π/180
a=〖30〗^( )= (30π )/180=π/6
h=b-a=(22/7)/180=0.0174
f(a)=f(π/6)=sin〖π/6〗=1/2=0.5
f^- (a)=f^- (π/6)=cos〖π/6=√3/2〗=0.866
f(a+h)=f(a)+hf^- (a)
f(31π/180)=f(π/6)+hf^- (π/6)
f(〖31〗^ )=0 .5+(0.0174 )(0.866)
sin〖〖31〗^ 〗=0.5+0.015
sin〖〖31〗^ 〗=0.515
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01-15-2012, 03:22 PM
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#2
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01-15-2012, 10:28 PM
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#3
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