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  1. Top | #1

    Apr 2012
    14804
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    Thanked: 119

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    area of ellipse








    suppose semimajor axis of ellipse = a , and semiminor axis = b


    The parametric formula of ellipse :

    y = b*sin j
    x = a*cos j

    area of one - quarter of ellipse = INT (0 to a ) y.dx

    dx = - a*sin j dj
    when x = 0 ..... j = pi/2
    when x = a ..... j = 0

    area = 4*INT (from j = pi/2 to j = 0) - b*a*sin^2 j .dj

    area = 4*INT (from j = 0 to j = pi/2)* a*b (1 - cos 2j)/2 . dj

    area = 2*a*b [j - 1/2*sin 2j]from j = 0 to j = pi/2

    area = 2*a*b [pi/2 - 0 - 1/2*sin pi + 1/2*sin 0

    area = pi*a*b
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    hyperbola







    Parabola






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    f-77



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    / hoor_dana



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    = 3

    :
    : ( 0 3 )
    1 : ( 6 3 )
    2 : ( - 6 3 )
    1 : ( 11 3 )
    2 : ( - 11 3 )


















  2. Top | #2

    Apr 2012
    14804
    -
    0.14
    598
    Thanked: 119
    msmm1399



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    15


    1- (0,_+3) (5,4)
    ()

    2- (1,1),(9,1)

    3- (,) (4,0)
    3-27=0

    4- =-3(,+5)-2( )

    5-
    (-3 ,6)





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  3. Top | #3

    Apr 2012
    14804
    -
    0.14
    598
    Thanked: 119

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  4. Top | #4

    Apr 2012
    14804
    -
    0.14
    598
    Thanked: 119



























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