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02-01-2016, 05:09 PM
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#1
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02-03-2016, 01:55 PM
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#2
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02-03-2016, 03:23 PM
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#3
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02-03-2016, 03:26 PM
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#4
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let n =number of elements of a set
then 2^ n^2= number of relations on it
n factorial =number of all bijective functions on it
so 2^n^2 is greater than n factorial
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02-03-2016, 05:03 PM
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02-13-2016, 01:51 PM
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#6
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02-13-2016, 02:16 PM
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#7
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02-13-2016, 09:48 PM
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#8
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02-14-2016, 06:17 PM
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02-15-2016, 12:44 PM
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#10
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02-15-2016, 12:49 PM
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#11
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02-23-2016, 10:25 PM
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#12
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