$\int_{1}^{5}\frac{x}{\sqrt{2x-1}}dx$
$=\int_{1}^{5}\frac{1+2x-1}{2\sqrt{2x-1}}dx$
$=\int_{1}^{5}\frac{1}{2\sqrt{2x-1}}dx+\int_{1}^{5}\frac{1}{2}\sqrt{2x-1}dx$
$=\frac{1}{2}\sqrt{2x-1}+\frac{1}{6}(2x-1)^{\frac{3}{2}}]_{1}^{5}$
$=\frac{16}{3}$
$\int_{1}^{5}\frac{x}{\sqrt{2x-1}}dx$
$=\int_{1}^{5}\frac{1+2x-1}{2\sqrt{2x-1}}dx$
$=\int_{1}^{5}\frac{1}{2\sqrt{2x-1}}dx+\int_{1}^{5}\frac{1}{2}\sqrt{2x-1}dx$
$=\frac{1}{2}\sqrt{2x-1}+\frac{1}{6}(2x-1)^{\frac{3}{2}}]_{1}^{5}$
$=\frac{16}{3}$
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