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  1. Top | #13

    Sep 2013
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    $\int_{1}^{5}\frac{x}{\sqrt{2x-1}}dx$

    $=\int_{1}^{5}\frac{1+2x-1}{2\sqrt{2x-1}}dx$

    $=\int_{1}^{5}\frac{1}{2\sqrt{2x-1}}dx+\int_{1}^{5}\frac{1}{2}\sqrt{2x-1}dx$

    $=\frac{1}{2}\sqrt{2x-1}+\frac{1}{6}(2x-1)^{\frac{3}{2}}]_{1}^{5}$

    $=\frac{16}{3}$

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