ÂÎÑ ÇáãÔÇÑßÇÊ

ÇáÒÇÆÑ ÇáßÑíã:ÊÓÊØíÚ ãÔÇåÏÉ ßá ÇáãæÇÖíÚ ÈÏæä ÔÑØ ÇáÚÖæíÉ áßä ãÔÇÑßÊß ÊÍÊÇÌ ÚÖæíÉ ÇáãäÊÏì
ÕÝÍÉ 1 ãä 5 12345 ÇáÃÎíÑÉÇáÃÎíÑÉ
ÇáäÊÇÆÌ 1 Åáì 12 ãä 49
  1. Top | #1

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÓáÓáÉ ÇáÊßÇãá ÇáãÍÏÏ

    $Q1)\space prove\ that\\ \int_{0}^{\infty }\frac{1-e^{-\sqrt{2}x}}{xe^x}dx=sinh^{-1}1$
    ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ÌÈÇÑ ÇáÍÓíäí ; 06-11-2016 ÇáÓÇÚÉ 01:02 AM
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  2. The Following 2 Users Say Thank You to ÝáÇÍ ÇáäÇÕÑí For This Useful Post:

     (05-29-2016),  (05-29-2016)

  3. Top | #2

    ÊÇÑíÎ ÇáÊÓÌíá
    Dec 2013
    ÑÞã ÇáÚÖæíÉ
    18045
    ÇááÞÈ
    ãä ÇÓÇÊÐÉ ÇáãäÊÏì
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.13
    ÇáÏæáÉ
    ÇáÚÑÇÞ - ÇáÈÕÑÉ
    ÇáãÔÇÑßÇÊ
    623
    Thanked: 1053

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    ÇáÓáÇã Úáíßã
    ÇÚÇäí ãÔßá ÈÑÝÚ ÇáãáÝÇÊ
    æÍÇæáÊ ÇáßÊÇÈÉ ÈØÑíÞÉ latex æáßä ÎÑÌ ÇáÍá ÛíÑ ãÑÊÈ

  4. The Following 2 Users Say Thank You to ÚÇÏá ÇáßÚÈí For This Useful Post:

     (05-29-2016),  (05-30-2016)

  5. Top | #3

    ÊÇÑíÎ ÇáÊÓÌíá
    Dec 2013
    ÑÞã ÇáÚÖæíÉ
    18045
    ÇááÞÈ
    ãä ÇÓÇÊÐÉ ÇáãäÊÏì
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.13
    ÇáÏæáÉ
    ÇáÚÑÇÞ - ÇáÈÕÑÉ
    ÇáãÔÇÑßÇÊ
    623
    Thanked: 1053

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    ÇáÓáÇã Úáíßã
    ÇÚÇäí ãÔßá ÈÑÝÚ ÇáãáÝÇÊ
    æÍÇæáÊ ÇáßÊÇÈÉ ÈØÑíÞÉ latex æáßä ÎÑÌ ÇáÍá ÛíÑ ãÑÊÈ

    ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ÌÈÇÑ ÇáÍÓíäí ; 05-29-2016 ÇáÓÇÚÉ 02:00 PM

  6. The Following 3 Users Say Thank You to ÚÇÏá ÇáßÚÈí For This Useful Post:

     (05-29-2016),  (06-14-2016),  (05-30-2016)

  7. Top | #4

    ÊÇÑíÎ ÇáÊÓÌíá
    Dec 2013
    ÑÞã ÇáÚÖæíÉ
    18045
    ÇááÞÈ
    ãä ÇÓÇÊÐÉ ÇáãäÊÏì
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.13
    ÇáÏæáÉ
    ÇáÚÑÇÞ - ÇáÈÕÑÉ
    ÇáãÔÇÑßÇÊ
    623
    Thanked: 1053

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    ÇÖØÑÑÊ Çáì ÇÊÈÇÚ åÐå ÇáØÑíÞÉ Ýí ÊÍãíá ÇáãÔÇÑßÇÊ ÈÓÈÈ ÇáãÔßáÉ ÇáÊí áÏí
    ÝÛÇáÈÇ ãÇíÙåÑ áí ÚäÏãÇ ÇÍÇæá ÑÝÚ ãáÝ ( ÝÔá ÇáÊÍãíá ÇáÕÝÍÉ áÇÊÚãá )
    [IMG] Image 67.jpg (90.9 ßíáæÈÇíÊ)[/IMG]
    ÇáÕæÑ ÇáãÑÝÞÉ ÇáÕæÑ ÇáãÑÝÞÉ

  8. The Following 3 Users Say Thank You to ÚÇÏá ÇáßÚÈí For This Useful Post:

     (05-29-2016),  (05-30-2016),  (05-07-2020)

  9. Top | #5

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    $Q2 \int_{0}^{\infty }\frac{e^{-3x^2}-e^{-4x^2}}{x}dx$
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  10. Top | #6

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    $\int_{0}^{\infty }\frac{e^{-3x^{2}}-e^{-4x^{2}}}{x}dx$
    $=\int_{0}^{\infty }\frac{1}{x}(e^{-ax^{2}})dx$
    $=\int_{0}^{\infty }(\int_{4}^{3}\frac{x^{2}e^{-ax^{2}}}{x}da)dx$
    $=\int_{4}^{3}(\int_{0}^{\infty }-xe^{-ax^{2}}dx)da$
    $=\int_{4}^{3}[\frac{e^{-ax^{2}}}{2a}]_{0}^{\infty }da$
    $=\int_{4}^{3}\frac{-1}{2a}da=\frac{-1}{2}lna=\frac{-1}{2}ln\frac{3}{4}$
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  11. Top | #7

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    $Q3\int_{0}^{\infty }\frac{\arctan(2x)-\arctan (3x) }{x}dx$
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  12. Top | #8

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    ááÊÐßíÑ ¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿ ¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  13. Top | #9

    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2014
    ÑÞã ÇáÚÖæíÉ
    18677
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ (ÎÈíÑ ÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.68
    ÇáãÔÇÑßÇÊ
    3,133
    Thanked: 3674

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá


  14. The Following User Says Thank You to ÕáÇÍ ÇÍãÏ For This Useful Post:

     (06-06-2016)

  15. Top | #10

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    $Q4)\int_{0.2}^{3.5}\left \lfloor x \right \rfloor dx$

    $Q5)\int_{0.2}^{3.5}\left \lceil x \right \rceil dx$
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  16. Top | #11

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá

    ááÊÐßíÑ ¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿ ¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  17. Top | #12

    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2014
    ÑÞã ÇáÚÖæíÉ
    18677
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ (ÎÈíÑ ÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.68
    ÇáãÔÇÑßÇÊ
    3,133
    Thanked: 3674

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá ÇáãÚÊá


  18. The Following 2 Users Say Thank You to ÕáÇÍ ÇÍãÏ For This Useful Post:

     (06-16-2016),  (06-10-2016)

ÕÝÍÉ 1 ãä 5 12345 ÇáÃÎíÑÉÇáÃÎíÑÉ

ãÚáæãÇÊ ÇáãæÖæÚ

ÇáÃÚÖÇÁ ÇáÐíä íÔÇåÏæä åÐÇ ÇáãæÖæÚ

ÇáÐíä íÔÇåÏæä ÇáãæÖæÚ ÇáÂä: 2 (0 ãä ÇáÃÚÖÇÁ æ 2 ÒÇÆÑ)

ÖæÇÈØ ÇáãÔÇÑßÉ

  • áÇ ÊÓÊØíÚ ÅÖÇÝÉ ãæÇÖíÚ ÌÏíÏÉ
  • áÇ ÊÓÊØíÚ ÇáÑÏ Úáì ÇáãæÇÖíÚ
  • áÇ ÊÓÊØíÚ ÅÑÝÇÞ ãáÝÇÊ
  • áÇ ÊÓÊØíÚ ÊÚÏíá ãÔÇÑßÇÊß
  •  

Powered by vBulletin® Version 4.2.3
Copyright © 2026 vBulletin Solutions, Inc. All rights reserved.
Translate By Almuhajir
Developed By Marco Mamdouh
Style
ÊØæíÑ æÏÚã ÔÑßÉ Zavord