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06-06-2016, 11:57 PM
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#1
ÓáÓáÉ ÇáãÚÇÏáÉ ÇáÊÝÇÖáíÉ : The differential equations series
\[Solve \: the \, differential\: equations:\, \, Q1a. \, \, \, \frac{\mathrm{d} y}{\mathrm{d} x}=\frac{x}{x^{2}+1}\]
\[Solve \: the \, differential\: equations:\, \,\\ Q1b. \, \, \,\left ( e^{x}+e^{-x} \right )\frac{dy}{dx} =\left ( e^{x}-e^{-x} \right )\]
ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ßÇãá ãæÓì ÇáäÇÕÑí ; 06-07-2016 ÇáÓÇÚÉ 01:09 AM
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06-07-2016, 04:36 AM
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#2
ÑÏ: ÓáÓáÉ ÇáãÚÇÏáÉ ÇáÊÝÇÖáíÉ : The differential equations series
\[{\color{Blue} Q1-b)}\\(e^{x}+e^{-x})\frac{dy}{dx}=(e^{x}-e^{-x})\\dy=\frac{e^{x}-e^{-x}}{e^{x}+e^{-x}}dx\\y=ln(e^{x}+e^{-x})+lnC\\y=lnC(e^{x}+e^{-x})\]
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