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    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2011
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    ÇáÚÑÇÞ 07701766668 / 07800055259
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    ÓáÓáÉ ÇáãÚÇÏáÉ ÇáÊÝÇÖáíÉ : The differential equations series

    \[Solve \: the \, differential\: equations:\, \, Q1a. \, \, \, \frac{\mathrm{d} y}{\mathrm{d} x}=\frac{x}{x^{2}+1}\]


    \[Solve \: the \, differential\: equations:\, \,\\ Q1b. \, \, \,\left ( e^{x}+e^{-x} \right )\frac{dy}{dx} =\left ( e^{x}-e^{-x} \right )\]
    ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ßÇãá ãæÓì ÇáäÇÕÑí ; 06-07-2016 ÇáÓÇÚÉ 01:09 AM

  2. The Following 3 Users Say Thank You to ßÇãá ãæÓì ÇáäÇÕÑí For This Useful Post:

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  3. Top | #2

    ÊÇÑíÎ ÇáÊÓÌíá
    Oct 2011
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    ÑÏ: ÓáÓáÉ ÇáãÚÇÏáÉ ÇáÊÝÇÖáíÉ : The differential equations series

    \[{\color{Blue} Q1-b)}\\(e^{x}+e^{-x})\frac{dy}{dx}=(e^{x}-e^{-x})\\dy=\frac{e^{x}-e^{-x}}{e^{x}+e^{-x}}dx\\y=ln(e^{x}+e^{-x})+lnC\\y=lnC(e^{x}+e^{-x})\]

  4. The Following 2 Users Say Thank You to ÍÇÌã ÇáÑÈíÚí For This Useful Post:

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