$Q19)solve .in.R$
$ tanx+tany=1$
$x+y=\frac{\pi }{4}$
$Q20)solve.in.[0,2\pi ]$
$sinx+siny=1$
$cos2x-cos2y=1$
; 06-25-2016 07:44 AM
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$\large {\color{Red} x+y=\frac{\pi}{4}\Rightarrow \tan(x+y)=1\Rightarrow 1-tanxtany=1}$
$\large {\color{Red} \tan(x)\tan(y)=0\Rightarrow x=n\pi ,,OR,, y=n\pi}$
\$\large {\color{Red} \rightarrow y=(\pi/4)-n\pi,,OR,,x=(\pi/4)-n\pi}$
$\large {\color{Red} cos2x-cos2y=1\Rightarrow 1-2sin^{2}x-1+2sin^{2}y=1}$
${\color{Red} \Rightarrow 2(sin^{2}y-sin^{2}x)=1\rightarrow (siny-sinx)(siny+sinx)=1/2} $
${\color{Red} \Rightarrow sinx+siny=1,,siny-sinx=1/2\Rightarrow siny=3/4,,sinx=1/4}$
$ {\color{Red} \Rightarrow x=0.24,,x=\pi-0.24,,y=0,88,,y=\pi-0.88}$
; 06-20-2016 12:10 AM
$Q21)solve.in.[0,2\pi ]$
$sinx+cosy=1$
$cos2x-cos2y=1$
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$Q22)1+\left | log_4{(9x^{2}-39x+43)} \right |=\left | cos((x-2)cosx) \right |$
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; 09-01-2016 04:44 PM
$Q23)solve in [0,\pi ]$
$sin^{8}x+cos^{8}x-cos^{2}2x=0$
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: 2 (0 2 )
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