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  1. Top | #25

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  3. Top | #26

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  5. Top | #27

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    $Q19)solve .in.R$

    $ tanx+tany=1$

    $x+y=\frac{\pi }{4}$


    $Q20)solve.in.[0,2\pi ]$

    $sinx+siny=1$

    $cos2x-cos2y=1$
    ; 06-25-2016 07:44 AM

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  7. Top | #28

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    $\large {\color{Red} x+y=\frac{\pi}{4}\Rightarrow \tan(x+y)=1\Rightarrow 1-tanxtany=1}$
    $\large {\color{Red} \tan(x)\tan(y)=0\Rightarrow x=n\pi ,,OR,, y=n\pi}$
    \$\large {\color{Red} \rightarrow y=(\pi/4)-n\pi,,OR,,x=(\pi/4)-n\pi}$

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  9. Top | #29

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    $\large {\color{Red} cos2x-cos2y=1\Rightarrow 1-2sin^{2}x-1+2sin^{2}y=1}$
    ${\color{Red} \Rightarrow 2(sin^{2}y-sin^{2}x)=1\rightarrow (siny-sinx)(siny+sinx)=1/2} $
    ${\color{Red} \Rightarrow sinx+siny=1,,siny-sinx=1/2\Rightarrow siny=3/4,,sinx=1/4}$
    $ {\color{Red} \Rightarrow x=0.24,,x=\pi-0.24,,y=0,88,,y=\pi-0.88}$
    ; 06-20-2016 12:10 AM

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  11. Top | #30

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    $Q21)solve.in.[0,2\pi ]$

    $sinx+cosy=1$

    $cos2x-cos2y=1$

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  13. Top | #31

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  14. Top | #32

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    $Q22)1+\left | log_4{(9x^{2}-39x+43)} \right |=\left | cos((x-2)cosx) \right |$

  15. Top | #33

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  17. Top | #34

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    ; 09-01-2016 04:44 PM

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  19. Top | #35

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    $Q23)solve in [0,\pi ]$

    $sin^{8}x+cos^{8}x-cos^{2}2x=0$

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  21. Top | #36

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    URL="http://alnasiry.net/forums"][/URL

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