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    $\large {\color{DarkBlue} \int \frac{1}{\sqrt{1-sin2x}}dx=\int \frac{1}{\sqrt{(sinx-cosx)^{2}}}}$
    $ {\color{DarkBlue} =\int \frac{1}{\sqrt{2}}\frac{1}{sin(x-\pi/4)}dx=1/\sqrt{2}\int \csc(x-\pi/4)dx}$
    ${\color{DarkBlue} =-1/\sqrt{2}\ln|cot(x-\pi/4)+csc(x-\pi/4)|+c}$
    ; 06-20-2016 05:54 PM

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    ; 06-20-2016 05:32 PM

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    \[\LARGE {\color{Blue} \int x\sqrt{-x^2+6x-8}dx}\]

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    \[\LARGE {\color{Blue} \int \frac{\sqrt{4x^2-4x+17}}{2x-1}dx}\]

  12. Top | #7

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    \[\LARGE {\color{Blue} \int \frac{\sqrt{4x^2-4x+17}}{2x-1}dx}\]
    [URL="http://alnasiry.net/forums"][IMG]http://alnasiry.net/forums/uploaded/2_iraqiflag.gif[/IMG][/URL]


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    \[\huge {\color{Red} {\color{Red} \int \frac{x^2}{1+x^6}dx}}\]

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