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    ÊÇÑíÎ ÇáÊÓÌíá
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  2. The Following User Says Thank You to ÈáÇá ÇáÚÑÇÞí For This Useful Post:

     (07-07-2016)

  3. Top | #2

    ÊÇÑíÎ ÇáÊÓÌíá
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    ÑÏ: ãËáËíÉ ÎÝíÝÉ ãÚ ÇáÊÕÑÝ

    [SIZE=5]SIZE=4]$\LARGE {\color{DarkOrange} sinA+sinB=\frac{-\sqrt{3}}{2}=2sin(\frac{A+B}{2})cos(\frac{A-B}{2})...(1)}$]
    ${\color{DarkOrange} cosA-cosB=\frac{1}{2}=-2sin(\frac{A+B}{2})sin(\frac{A-B}{2})...(2)}$
    $ {\color{DarkOrange} (1)/(2)=cot(\frac{A-B}{2})=\sqrt{3}\rightarrow \frac{A-B}{2}=\frac{\pi}{b}\rightarrow A-B=\frac{\pi}{3}}$
    ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ Ìáíá ÇáÒíÇÏí ; 07-08-2016 ÇáÓÇÚÉ 12:07 AM

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  5. Top | #4

    ÊÇÑíÎ ÇáÊÓÌíá
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