2011 - 2012 01 ( ) \
/
- 3
lnln1= ????
( ) \ 11 \ ...
f(x) lnln1
- 43
hatim alrawi ln(ln(4)=ln((1.3863)=0.3266 )(1)ln(x)>0 ln(x) x>0
[URL="http://alnasiry.net/forums"][IMG]http://alnasiry.net/forums/uploaded/2_iraqiflag.gif[/IMG][/URL] Evaluate 2
(09-04-2013)
\ \ ...Exponential Limits \\ \ 3
hatim alrawi
[URL="http://alnasiry.net/forums"][IMG]http://alnasiry.net/forums/uploaded/2_iraqiflag.gif[/IMG][/URL]
6 - ... \ 6 \2
: 1 (0 1 )
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