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    \[\begin{align}
    & \int{\frac{{{x}^{3}}}{{{\left( 1-x \right)}^{5}}}}\,dx \\
    & =\int{\frac{{{x}^{3}}}{{{x}^{5}}{{\left( \frac{1}{x}-1 \right)}^{5}}}}\,dx \\
    & =-\int{{{\left( \frac{1}{x}-1 \right)}^{-5}}}\,\left( -\frac{1}{{{x}^{2}}} \right)dx \\
    & =\frac{1}{4}{{\left( \frac{1}{x}-1 \right)}^{-4}}+C \\
    & =\frac{1}{4}{{\left( \frac{x}{1-x} \right)}^{4}}+C \\
    \end{align}\]

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