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  3. Top | #2

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    q6)

    a+b+c=(a+b-c)+(b+c-a)+(c+a-b)


    using Am-GM WE HAVE

    (a+b+c)/ 3 > or = third root of (a+b_c)(b+c-a)(c+A-b)





    by cubing both sides we get the required result

: 1 (0 1 )


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