:
1 12 12

:

  1. Top | #1

    Feb 2011
    2
    1.89
    07701766668 / 07800055259
    9,116
    Thanked: 7411



    ; 02-07-2013 10:28 PM

  2. Top | #2

    Feb 2011
    2
    1.89
    07701766668 / 07800055259
    9,116
    Thanked: 7411




    ; 02-07-2013 09:42 PM

  3. Top | #3

    Nov 2011
    1063
    0.25
    1,154
    Thanked: 500



  4. Top | #4

    Nov 2011
    1063
    0.25
    1,154
    Thanked: 500

  5. Top | #5

    Nov 2011
    1063
    0.25
    1,154
    Thanked: 500

    ; 02-07-2013 02:53 AM

  6. Top | #6

    Dec 2012
    15310
    0.00
    14
    Thanked: 0


  7. Top | #7

    Feb 2011
    2
    1.89
    07701766668 / 07800055259
    9,116
    Thanked: 7411

    ; 02-07-2013 10:31 PM

  8. The Following User Says Thank You to For This Useful Post:

     (12-02-2015)

  9. Top | #8

    Feb 2014
    18610
    0.02
    64
    Thanked: 145

    :



    ; 11-30-2015 11:40 AM :

  10. Top | #9

    Feb 2014
    18610
    0.02
    64
    Thanked: 145

    :


  11. The Following User Says Thank You to For This Useful Post:

     (11-30-2015)

  12. Top | #10

    Feb 2014
    18610
    0.02
    64
    Thanked: 145

    :




  13. The Following User Says Thank You to For This Useful Post:

     (11-30-2015)

  14. Top | #11

    Feb 2014
    18677
    ( )
    0.72
    2,676
    Thanked: 3386

    :

    x is positive and not equal 1

  15. The Following User Says Thank You to For This Useful Post:

     (11-30-2015)

  16. Top | #12

    Feb 2014
    18677
    ( )
    0.72
    2,676
    Thanked: 3386

    :

    q6)

    a+b+c=(a+b-c)+(b+c-a)+(c+a-b)


    using Am-GM WE HAVE

    (a+b+c)/ 3 > or = third root of (a+b_c)(b+c-a)(c+A-b)





    by cubing both sides we get the required result

: 1 (0 1 )


Powered by vBulletin® Version 4.2.3
Copyright © 2024 vBulletin Solutions, Inc. All rights reserved.
Translate By Almuhajir
Developed By Marco Mamdouh
Style
Zavord