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  1. Top | #1

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    Question

    [CENTER][B][SIZE=7][CENTER]





    -i . ER]

  2. Top | #2

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  3. Top | #3

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    -i
    (x+yi) -i
    Then (x+yi)2 = -i

    X2+2xy+y2i2= 0-i
    X2-y2=0 (1)
    2xy=-1
    Then y=-1/ 2x (2)
    By substituted from equ.2 with equ.1 result :
    X2- 1/ 4x2 = 0
    4x2
    4x4-1=0
    (2x2-1)(2x2+1)=0

    X2= - 1/2
    ( x R)

    x=1/ 2
    2 x
    y= - (1/ (2) 1/ 2)
    = 1/ 2
    2

  4. Top | #4

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    2
    2 2

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    2
    ; 04-17-2013 11:03 AM :

  6. Top | #6

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  7. Top | #7

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    2 x

  8. Top | #8

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    2 2 2


  9. Top | #9

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    2 2 2

    2 2 2 . .

  10. Top | #10

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