... 9 wolfram 1
... - ... ...
=9 (1+2)(2/6) =1
... w ( )
= 1
transcendental numbers ... - ...... elimit by substitution
...........
... 2014 \ /
... 9 wolfram 1 62(2+1) 2 3 ( (2 (2+1) 6(2(2+1))
[URL="http://alnasiry.net/forums"][IMG]http://alnasiry.net/forums/uploaded/2_iraqiflag.gif[/IMG][/URL] Permutations and combinations
: 1 (0 1 )
Powered by vBulletin® Version 4.2.3 Copyright © 2026 vBulletin Solutions, Inc. All rights reserved. Translate By AlmuhajirDeveloped By Marco Mamdouh Style Zavord