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06-12-2015, 12:12 PM
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#1
; 06-12-2015 01:54 PM
: (9)
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06-12-2015, 03:22 PM
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#2
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06-12-2015, 06:15 PM
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#3
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06-12-2015, 07:04 PM
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#4
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06-12-2015, 10:05 PM
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#5
: (9)
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06-13-2015, 12:12 AM
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#6
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06-13-2015, 01:06 AM
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#7
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06-13-2015, 04:46 AM
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#8
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06-13-2015, 07:24 AM
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#9
: (9)
a/1 =b/x=c/(1-x^2)=k
a=k and b=kx. And c=k(1-x^2)
Then a^2-b^2=ac
BC^2-AC^2=BC*AB
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06-14-2015, 12:53 AM
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#10
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06-14-2015, 08:03 AM
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#11
: (9)
٦٠ 2 cos theta Is between 1 and 2 then x is between 1. And 2
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