Íá ÇáäÙÇã Ýì Ø
\displaystyle{\begin{cases}x^{x+y}=y^n \\ y^{x+y}=x^{2n}y^n \end{cases},n \in \mathbb N^{*}}
Íá ÇáäÙÇã Ýì Ø
\displaystyle{\begin{cases}x^{x+y}=y^n \\ y^{x+y}=x^{2n}y^n \end{cases},n \in \mathbb N^{*}}
ääÊÙÑ ÇáÍá ãä ÇáãÈÏÚíä
$\large {\color{DarkBlue} let, x+y=m\Rightarrow x^{m}=y^{n}\Rightarrow mlnx=nlny\Rightarrow lnx=\frac{nlny}{m}}$
${\color{DarkBlue} y^{m}=x^{2n}y^{n}\Rightarrow mlny=2nlnx+nlny\Rightarrow mlny=\frac{2n^{2}lny}{m}+nlny}$
${\color{DarkBlue} \Rightarrow m^{2}-mn-2n^{2}=0\rightarrow (m-2n)(m+n)=0} $
${\color{DarkBlue} if,m=2n\rightarrow x^{2n}=y^{n}\rightarrow y=x^{2}\rightarrow S1={(1,1),(2,4),...}}$
$ {\color{DarkBlue} if,m=-n\rightarrow x^{-n}=y^{n}\rightarrow y=\frac{1}{x}\rightarrow S2=(1,1)}$
ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ Ìáíá ÇáÒíÇÏí ; 06-22-2016 ÇáÓÇÚÉ 04:54 PM
ÇáÐíä íÔÇåÏæä ÇáãæÖæÚ ÇáÂä: 1 (0 ãä ÇáÃÚÖÇÁ æ 1 ÒÇÆÑ)
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