$let \ p(x,y) \in \ Eillps \ and \ (0,-3)=\ F(0 ,-p)$
$D=\sqrt{x^2 +y^2+6y+9}=\sqrt{26}$
$ x^2+y^2+6x+9=26$
$ 4x^2 +4y^2+24y-68=0$
$8-y^2+4y^2+24y-68=0$
$3y^2+24y-60=0$
$y^2+8y-20=0$
$(y+10)(y-2)=0$
$y=-10 \ then 4x^2=-92 \ Ref \ OR \ y= 2 \ then x^2=1$
$ Then \ the\ points (1,2) , (-1,2)$
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