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    $let \ p(x,y) \in \ Eillps \ and \ (0,-3)=\ F(0 ,-p)$
    $D=\sqrt{x^2 +y^2+6y+9}=\sqrt{26}$
    $ x^2+y^2+6x+9=26$
    $ 4x^2 +4y^2+24y-68=0$
    $8-y^2+4y^2+24y-68=0$
    $3y^2+24y-60=0$
    $y^2+8y-20=0$
    $(y+10)(y-2)=0$
    $y=-10 \ then 4x^2=-92 \ Ref \ OR \ y= 2 \ then x^2=1$
    $ Then \ the\ points (1,2) , (-1,2)$

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