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  1. Top | #1

    Mar 2011
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  2. Top | #2

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    a,b c c a b a c a,b .
    ; 02-13-2017 06:35 AM

  3. The Following User Says Thank You to For This Useful Post:

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  4. Top | #3

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    a,b c c a b a c a,b .

    a ,b b>a a,b ߿

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    a,b a b [f(a)-f(b)]/a-b f(b)=f(a)-(a-b)f'(a)

  6. Top | #5

    Mar 2011
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    a,b a b [f(a)-f(b)]/a-b f(b)=f(a)-(a-b)f'(a)
    a,b
    c

: 1 (0 1 )


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