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  1. Top | #1

    Dec 2011
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    x :

    log_{4}log_{2}log_{3}x^{8}=1

    /

    let: log_{2}log_{3}x^{8}=x

    log_{4}x=1

    x=4^{1

    x=4

    log_{2}log_{3}x^{8}=4

    let log_{3}x^{8}=y


    log_{2}y=4


    y=2^{4


    y=16

    log_{3}x^{8}=16


    x^{8}=3^{16


    x^{8}=3^{2^{8

    x^{8}=9^{8

    x=9

  2. Top | #2

    Oct 2011
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  3. Top | #3

    Dec 2011
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