[CENTER][B][SIZE=7][CENTER]
-i . ER]
[CENTER][B][SIZE=7][CENTER]
-i . ER]
-i
(x+yi) -i
Then (x+yi)2 = -i
X2+2xy+y2i2= 0-i
X2-y2=0 (1)
2xy=-1
Then y=-1/ 2x (2)
By substituted from equ.2 with equ.1 result :
X2- 1/ 4x2 = 0
4x2
4x4-1=0
(2x2-1)(2x2+1)=0
X2= - 1/2
( x R)
x=1/ 2
2 x
y= - (1/ (2) 1/ 2)
= 1/ 2
2
2
; 04-17-2013 11:03 AM :
: 1 (0 1 )
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