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    Dec 2013
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    1:-
    1- (3i )/(√2 +i ) - 3i/(√2 -i) = 2
    2- √((1+10w+10w^2)/(1-3w- 3w^2 ))= 3i/2
    2:- X , Y :
    1- (1-i )/(1+i ) X+( 1+3i )^(2 ) Y=(1-i)(1+3i)
    / X=-1, Y=-1/2
    2- 6/(X+iY ) (3+i)/(2-i )=(1-i)^3
    / X= -3 , Y= 3
    3- √((iw^(2 )+ i)/w^2 ) =xw+ywi
    / x=1/√2 , y=-1/√2
    4- (2 + xi)(- x + i) = (9y^2+ 49)/(3y+7i )
    / x=3 ,y=-3
    5- x(x +i) + y(y - i) + i = 13
    / x= -3 , y = -2
    6- (2x + i)(y 2i) = -2 9i
    / x = 1/4 , y = - 8
    7- (3x i)(2y + i) + 11 = 7i
    / x = 1 , y = -2
    8- (1-i )/(1+i ) x+ 〖(1+3i)〗^2 y =(1-i)(1+3i)
    / x=-5 , y =-1/2
    9- x + yi (3 + 2i)2 = (7-4i )/(2+i )
    /x = 7 , y= 9
    10- (x y 6) + (y2 x)i = 0
    /x = 2 , y= 3
    3:- (3 + 5i)
    4:- Z = (1- √3 i)/(1+ √(-3)) :
    1- 2- 3-
    5:- C = - 1 + 2i C2 +3C + 5 / -1 + 2i
    6:- X = 2 + 3i , Y = 3 i X2 + 2Y2 / 11
    7:- (-2 + i) (3 + 2i)
    " / -8/65 + i/65
    8:- "
    1- (1 - √3 i )2 + (2 - √3 i )2 / - 1 - 6√3 i
    2- (1 + 3i)2 + (3 2i)2 / - 3 6i
    3- (3 + 4i)2 + (5 3i )(1 + i) / 1 + 26i
    4- 〖((3-i )/(1+i ))〗^2 /- 3 4i
    5- 1/i+ 1/(1-i ) / 1/2- i/2

    9:- = 1( 〖(2+i)〗^2/(3+4i ))


    10:- X , Y
    (x + 2iy) = (2 + i) ( x2+4y2) / x = , y=
    ; 12-26-2013 07:58 PM

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  3. Top | #2

    Oct 2011
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