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[SIZE=5]ÇáÓáÇã Úáíßã æÑÍãÉ Çááå æÈÑßÇÊå[/SIZE]
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ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ãÕØÝì ÓÚÝÇä ; 05-14-2014 ÇáÓÇÚÉ 08:38 PM
ÖÚ 3x+3 =y
The integral = integral of arc sin y / (sqrt (y^2 +25)*1/3dy
1/3 *i
I=integral of arcsin (y/(sqrt (y^2+25)
=integral of arc tan y/5
=y*arctan y/5- integral of y* 1/5 \(1+y^2+/25)
=y*arctan y/5-1/2 arctan y/5
Ëã äÚæÖ Úä ÞíãÉ y
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ÇáÐíä íÔÇåÏæä ÇáãæÖæÚ ÇáÂä: 1 (0 ãä ÇáÃÚÖÇÁ æ 1 ÒÇÆÑ)
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