:
1 12 12

: ...

  1. Top | #1

    Jul 2012
    15045
    0.27
    1,165
    Thanked: 827

    ...








  2. Top | #2

    Feb 2014
    18677
    ( )
    0.72
    2,666
    Thanked: 3381

    : ...

    i^(4*1/2)=(i^4)^(1/2)
    ( a^(m/n)=(a^m)^(1/n) a n

  3. Top | #3

    Jul 2012
    15045
    0.27
    1,165
    Thanked: 827

    : ...

    i^(4*1/2)=(i^4)^(1/2)
    ( a^(m/n)=(a^m)^(1/n) a n
    ...

  4. Top | #4

    Dec 2013
    18045
    0.17
    -
    623
    Thanked: 1053

    : ...


  5. Top | #5

    Jul 2012
    15045
    0.27
    1,165
    Thanked: 827

    : ...

    ... ( ) .

    ...

  6. Top | #6

    Dec 2013
    18045
    0.17
    -
    623
    Thanked: 1053

    : ...


  7. Top | #7

    Jul 2012
    15045
    0.27
    1,165
    Thanked: 827

    : ...

    ...

    ...

  8. Top | #8

    Dec 2013
    18045
    0.17
    -
    623
    Thanked: 1053

    : ...

    ( )

  9. Top | #9

    Feb 2014
    18677
    ( )
    0.72
    2,666
    Thanked: 3381

    : ...


  10. The Following User Says Thank You to For This Useful Post:

     (12-06-2014)

  11. Top | #10

    Jul 2012
    15045
    0.27
    1,165
    Thanked: 827

    : ...




    ...

    .. :



  12. Top | #11

    Feb 2014
    18677
    ( )
    0.72
    2,666
    Thanked: 3381

    : ...


    (
    i^4)^1/2=1^ 1/2=(cos0+isin0)^1/2=+or-(cos0+isin0)=+or-1
    (I^1/2)^4=(+or-(cos pi/4+isin pi/4)^4=cos pi+isin pi=-1
    (i^4)^1/2not equal (i^ 1/2)^4

  13. Top | #12

    Jul 2012
    15045
    0.27
    1,165
    Thanked: 827

    : ...

    ..

    ...

: 1 (0 1 )


Powered by vBulletin® Version 4.2.3
Copyright © 2024 vBulletin Solutions, Inc. All rights reserved.
Translate By Almuhajir
Developed By Marco Mamdouh
Style
Zavord