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  1. 06-01-2016, 10:27 AM Top | #13
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  2. 06-02-2016, 12:31 PM Top | #14
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    ; 06-02-2016 01:27 PM



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  4. 06-02-2016, 01:50 PM Top | #15
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    (2,5)

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  6. 06-04-2016, 02:06 PM Top | #16
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  7. 08-05-2016, 05:56 PM Top | #17
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  8. 08-05-2016, 06:09 PM Top | #18
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  10. 08-06-2016, 04:48 AM Top | #19
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    \[2ydx=3xdy\Rightarrow \frac{3dy}{y}=\frac{2dx}{x}\\3ln|y|=2ln|x|+lnC \\ y^3=Cx^2\\x=2,y=1\\1=4C\therefore C=\frac{1}{4}\\\therefore4y^3=x^2\]
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  12. 08-09-2016, 11:23 AM Top | #20
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  14. 08-09-2016, 05:43 PM Top | #21
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  15. 08-09-2016, 06:19 PM Top | #22
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  17. 08-10-2016, 02:15 AM Top | #23
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    ???????????????????????!!!!!!!!!!!!!!!!!!!!!!!!!!! !!



  18. 08-10-2016, 09:58 AM Top | #24
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