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    $Q1)\space prove\ that\\ \int_{0}^{\infty }\frac{1-e^{-\sqrt{2}x}}{xe^x}dx=sinh^{-1}1$
    ; 06-11-2016 01:02 AM

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    latex

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    latex

    ; 05-29-2016 02:00 PM

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    [IMG] Image 67.jpg (90.9 )[/IMG]

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    $Q2 \int_{0}^{\infty }\frac{e^{-3x^2}-e^{-4x^2}}{x}dx$

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    $\int_{0}^{\infty }\frac{e^{-3x^{2}}-e^{-4x^{2}}}{x}dx$
    $=\int_{0}^{\infty }\frac{1}{x}(e^{-ax^{2}})dx$
    $=\int_{0}^{\infty }(\int_{4}^{3}\frac{x^{2}e^{-ax^{2}}}{x}da)dx$
    $=\int_{4}^{3}(\int_{0}^{\infty }-xe^{-ax^{2}}dx)da$
    $=\int_{4}^{3}[\frac{e^{-ax^{2}}}{2a}]_{0}^{\infty }da$
    $=\int_{4}^{3}\frac{-1}{2a}da=\frac{-1}{2}lna=\frac{-1}{2}ln\frac{3}{4}$

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    $Q3\int_{0}^{\infty }\frac{\arctan(2x)-\arctan (3x) }{x}dx$

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    $Q4)\int_{0.2}^{3.5}\left \lfloor x \right \rfloor dx$

    $Q5)\int_{0.2}^{3.5}\left \lceil x \right \rceil dx$

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