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ÇáÒÇÆÑ ÇáßÑíã:ÊÓÊØíÚ ãÔÇåÏÉ ßá ÇáãæÇÖíÚ ÈÏæä ÔÑØ ÇáÚÖæíÉ áßä ãÔÇÑßÊß ÊÍÊÇÌ ÚÖæíÉ ÇáãäÊÏì
ÕÝÍÉ 2 ãä 8 ÇáÃæáìÇáÃæáì 12345678 ÇáÃÎíÑÉÇáÃÎíÑÉ
ÇáäÊÇÆÌ 13 Åáì 24 ãä 86

ÇáãæÖæÚ: ÓáÓáÉ ÇáÊßÇãá

  1. Top | #13

  2. The Following 2 Users Say Thank You to Ìáíá ÇáÒíÇÏí For This Useful Post:

     (06-09-2016),  (06-08-2016)

  3. Top | #14

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
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    ÇÓÊÇÐ ãÊãíÒ
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    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
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    ÑÏ: ÓáÓáÉ ÇáÊßÇãá

    $Q11)\int \frac{1}{\sqrt{sin^{3}x sin(x+3)}}dx$

    $Q12)\int \frac{cos5x+cos4x}{1-2cos3x}dx$

    $Q13)\int \frac{1}{1+2sin^{2}x}dx$

    $Q14) \int \frac{tanx}{cotx+tanx}dx$

    $Q15)\int \frac{sinx}{cotx+tanx}dx$

    $Q16)\int \frac{cosx}{cotx+tanx}dx$

    $Q17)\int \frac{cosx}{2+3sinx+sin^{2}x}dx$

    $Q18)\int \frac{cosx}{1+2sinx+sin^{2}x}dx$

    $Q19)\int \sqrt{cotx}dx$

    $Q20)\int (\sqrt{cotx}+\sqrt{tanx})dx$



    ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ÝáÇÍ ÇáäÇÕÑí ; 06-10-2016 ÇáÓÇÚÉ 12:59 AM
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  4. The Following User Says Thank You to ÝáÇÍ ÇáäÇÕÑí For This Useful Post:

     (06-09-2016)

  5. Top | #15

    ÊÇÑíÎ ÇáÊÓÌíá
    Aug 2013
    ÑÞã ÇáÚÖæíÉ
    16811
    ÇááÞÈ
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    ãÚÏá ÇáãÔÇÑßÇÊ
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    ÑÏ: ÓáÓáÉ ÇáÊßÇãá

    ÈÓã Çááå . äÙÑÇ áÌãÇáíÉ ÇáÓÄÇá Q10 , åÐÇ Íá ËÇäí ÈÚÏ ÇáÍá ÇáÌãíá ááÇÓÊÇÐ Ìáíá ÇáÒíÇÏí ÇáãÍÊÑã .




  6. The Following 2 Users Say Thank You to ãÍãÏ ÚÞíá For This Useful Post:

     (06-09-2016),  (06-09-2016)

  7. Top | #16

  8. The Following 2 Users Say Thank You to Ìáíá ÇáÒíÇÏí For This Useful Post:

     (06-09-2016),  (06-09-2016)

  9. Top | #17

    ÊÇÑíÎ ÇáÊÓÌíá
    May 2014
    ÑÞã ÇáÚÖæíÉ
    19175
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    ÇÓÊÇÐ ãÊãíÒ ( ÎÈíÑÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.38
    ÇáãÔÇÑßÇÊ
    1,725
    Thanked: 2677

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá

    [IMG]$\huge {\color{Red} \int (\frac{\tan x}{\cot x+\tan x})dx=\int (\frac{1}{\cot ^{2}x+1})dx =\int \sin ^{2}xdx=1/2[x-1/2\sin 2x]+c}$ [/IMG]

  10. The Following 2 Users Say Thank You to Ìáíá ÇáÒíÇÏí For This Useful Post:

     (06-09-2016),  (06-10-2016)

  11. Top | #18

    ÊÇÑíÎ ÇáÊÓÌíá
    May 2014
    ÑÞã ÇáÚÖæíÉ
    19175
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ ( ÎÈíÑÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
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    ÑÏ: ÓáÓáÉ ÇáÊßÇãá

    $\huge {\color{Blue} \int (\frac{\sin }{\cot x+\tan x})dx=\int (\frac{\sin x}{\frac{1}{\sin x\cos x}})dx=\int(\sin ^{2}x\cos x)dx=1/3 \sin ^{3}x+c }$

  12. The Following 2 Users Say Thank You to Ìáíá ÇáÒíÇÏí For This Useful Post:

     (06-09-2016),  (06-10-2016)

  13. Top | #19

    ÊÇÑíÎ ÇáÊÓÌíá
    May 2014
    ÑÞã ÇáÚÖæíÉ
    19175
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ ( ÎÈíÑÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.38
    ÇáãÔÇÑßÇÊ
    1,725
    Thanked: 2677

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá

    $\huge {\color{Blue}\int (\frac{\cos x}{\tan x+\cos x})dx=\int (\frac{\cos x}{\frac{1}{\sin x\cos x}})dx=\int (\cos ^{2}x)\sin xdx=-1/3\cos ^{3}x+c }$

  14. The Following 2 Users Say Thank You to Ìáíá ÇáÒíÇÏí For This Useful Post:

     (06-09-2016),  (06-10-2016)

  15. Top | #20

    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2014
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    ÑÏ: ÓáÓáÉ ÇáÊßÇãá


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  17. Top | #21

    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2014
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    18677
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ (ÎÈíÑ ÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
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    ÑÏ: ÓáÓáÉ ÇáÊßÇãá


  18. The Following User Says Thank You to ÕáÇÍ ÇÍãÏ For This Useful Post:

     (06-10-2016)

  19. Top | #22

    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2014
    ÑÞã ÇáÚÖæíÉ
    18677
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ (ÎÈíÑ ÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
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    Thanked: 3674

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá


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  21. Top | #23

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
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    Thanked: 1595

    ÑÏ: ÓáÓáÉ ÇáÊßÇãá

    ÓÄÇá12 ááÊÐßíÑ ¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿¿ ¿¿¿¿¿
    ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ÝáÇÍ ÇáäÇÕÑí ; 06-10-2016 ÇáÓÇÚÉ 04:16 AM
    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  22. The Following User Says Thank You to ÝáÇÍ ÇáäÇÕÑí For This Useful Post:

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  23. Top | #24

    ÊÇÑíÎ ÇáÊÓÌíá
    Aug 2013
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    16811
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    ÑÏ: ÓáÓáÉ ÇáÊßÇãá

    ÈÓã Çááå . Íá ÓÄÇá 12 / Q12 ÊÈÏæ ÇáÕæÑÉ ßÈíÑÉ ÚáãÇ Çä ÍÌãåÇ 52.1 kB



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