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ÇáÒÇÆÑ ÇáßÑíã:ÊÓÊØíÚ ãÔÇåÏÉ ßá ÇáãæÇÖíÚ ÈÏæä ÔÑØ ÇáÚÖæíÉ áßä ãÔÇÑßÊß ÊÍÊÇÌ ÚÖæíÉ ÇáãäÊÏì
ÕÝÍÉ 2 ãä 2 ÇáÃæáìÇáÃæáì 12
ÇáäÊÇÆÌ 13 Åáì 21 ãä 21

ÇáãæÖæÚ: ÊßÇãá

  1. Top | #13

    ÊÇÑíÎ ÇáÊÓÌíá
    Nov 2013
    ÑÞã ÇáÚÖæíÉ
    17896
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    ãä ÇÓÇÊÐÉ ÇáãäÊÏì
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.14
    ÇáãÔÇÑßÇÊ
    655
    Thanked: 1280

    ÑÏ: ÊßÇãá

    ÇáÓáÇã Úáíßã æÑÍãÉ Çááå æÈÑßÇÊå

    \[\huge {\color{Red} {\color{Red} \int \frac{sinx}{cosx(1+cos^2x)}dx}}\]

  2. The Following User Says Thank You to ãÕØÝì ÓÚÝÇä For This Useful Post:

     (06-28-2016)

  3. Top | #14

    ÊÇÑíÎ ÇáÊÓÌíá
    Nov 2011
    ÑÞã ÇáÚÖæíÉ
    1063
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
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    ÇáÏæáÉ
    ÞÑíÉ ÇáÕáÚÇ ÓæåÇÌ ãÕÑ
    ÇáãÔÇÑßÇÊ
    1,155
    Thanked: 503

    ÑÏ: ÊßÇãá

    ÇáÓáÇã Úáíßã æÑÍãÉ Çááå æÈÑßÇÊå íÇãæÌåäÇ ÇáßÈíÑ ÇÈæ ÇÍãÏ
    äÖÚ y=cosx æäÓÊÎÏã Çáß ÇáÌÒÆíå

  4. The Following 2 Users Say Thank You to Úáì ãÍãÏ ÇáãÕÑì For This Useful Post:

     (06-29-2016),  (06-28-2016)

  5. Top | #15

    ÊÇÑíÎ ÇáÊÓÌíá
    May 2014
    ÑÞã ÇáÚÖæíÉ
    19175
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ ( ÎÈíÑÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.38
    ÇáãÔÇÑßÇÊ
    1,725
    Thanked: 2677

    ÑÏ: ÊßÇãá

    ÇáÓáÇã Úáíßã æÑÍãÉ Çááå
    $\LARGE {\color{DarkBlue} \int \frac{sinx}{cosx(1+cos^{2}x)}dx=\int \frac{tanx*sec^{2}x}{sec^{2}x+1}dx=\frac{1}{2}ln|s ec^{2}x+1|+c}$

  6. The Following 2 Users Say Thank You to Ìáíá ÇáÒíÇÏí For This Useful Post:

     (06-29-2016),  (06-28-2016)

  7. Top | #16

    ÊÇÑíÎ ÇáÊÓÌíá
    Sep 2013
    ÑÞã ÇáÚÖæíÉ
    17034
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.28
    ÇáÏæáÉ
    ÇáÚÑÇÞ / Ðí ÞÇÑ
    ÇáãÔÇÑßÇÊ
    1,349
    Thanked: 1595

    ÑÏ: ÊßÇãá


    $\int \frac{x^{2}}{1+x^{6}}dx$

    $=\frac{1}{3}\int \frac{3x^{2}}{1+(x^{3})^{2}}dx$

    $=\frac{1}{3}arctan(x^{3})+c$

    "ÇáÑíÇÖíÇÊ åí Êáß ÇáãÊÚÉ ÇáÊí íÈÍË ÚäåÇ ÇáÃÐßíÇÁ æíÍÇæáæä ÇÓÊßÔÇÝ ÃÓÑÇÑåÇ æÍá ãÌåæáÇÊåÇ"
    ãä ãæÇÖíÚ


  8. The Following 2 Users Say Thank You to ÝáÇÍ ÇáäÇÕÑí For This Useful Post:

     (06-29-2016),  (07-02-2016)

  9. Top | #17

    ÊÇÑíÎ ÇáÊÓÌíá
    Nov 2013
    ÑÞã ÇáÚÖæíÉ
    17896
    ÇááÞÈ
    ãä ÇÓÇÊÐÉ ÇáãäÊÏì
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.14
    ÇáãÔÇÑßÇÊ
    655
    Thanked: 1280

    ÑÏ: ÊßÇãá

    ÇáÓáÇã Úáíßã æÑÍãÉ Çááå æÈÑßÇÊå
    \[\huge {\color{Red} {\color{Red} \int \frac{x-1}{(x+1)\sqrt{x(x^2+x+1)}}dx}}\]

  10. The Following 2 Users Say Thank You to ãÕØÝì ÓÚÝÇä For This Useful Post:

     (08-22-2016),  (07-02-2016)

  11. Top | #18

    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2014
    ÑÞã ÇáÚÖæíÉ
    18677
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ (ÎÈíÑ ÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.68
    ÇáãÔÇÑßÇÊ
    3,158
    Thanked: 3677

    ÑÏ: ÊßÇãá

    íáÛì ÇáÍá áæÌæÏ ÇÎØÇÁ
    ÇáÊÚÏíá ÇáÃÎíÑ Êã ÈæÇÓØÉ ÕáÇÍ ÇÍãÏ ; 06-30-2016 ÇáÓÇÚÉ 02:29 PM

  12. Top | #19

  13. The Following 3 Users Say Thank You to Ìáíá ÇáÒíÇÏí For This Useful Post:

     (07-01-2016),  (06-30-2016),  (08-22-2016)

  14. Top | #20

    ÊÇÑíÎ ÇáÊÓÌíá
    Nov 2013
    ÑÞã ÇáÚÖæíÉ
    17896
    ÇááÞÈ
    ãä ÇÓÇÊÐÉ ÇáãäÊÏì
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.14
    ÇáãÔÇÑßÇÊ
    655
    Thanked: 1280

    ÑÏ: ÊßÇãá

    ÇáÓáÇã Úáíßã æÑÍãÉ Çááå æÈÑßÇÊå

    \[\huge {\color{Red} {\color{Red} \int_{0}^{\pi }ln\frac{1+xcos\theta }{1-xcos\theta }\frac{d\theta }{cos\theta }such that\left | x \right |< 1}}\]

  15. The Following User Says Thank You to ãÕØÝì ÓÚÝÇä For This Useful Post:

     (07-02-2016)

  16. Top | #21

    ÊÇÑíÎ ÇáÊÓÌíá
    Feb 2014
    ÑÞã ÇáÚÖæíÉ
    18677
    ÇááÞÈ
    ÇÓÊÇÐ ãÊãíÒ (ÎÈíÑ ÚÇã)
    ãÚÏá ÇáãÔÇÑßÇÊ
    0.68
    ÇáãÔÇÑßÇÊ
    3,158
    Thanked: 3677

    ÑÏ: ÊßÇãá


  17. The Following User Says Thank You to ÕáÇÍ ÇÍãÏ For This Useful Post:

     (07-02-2016)

ÕÝÍÉ 2 ãä 2 ÇáÃæáìÇáÃæáì 12

ãÚáæãÇÊ ÇáãæÖæÚ

ÇáÃÚÖÇÁ ÇáÐíä íÔÇåÏæä åÐÇ ÇáãæÖæÚ

ÇáÐíä íÔÇåÏæä ÇáãæÖæÚ ÇáÂä: 1 (0 ãä ÇáÃÚÖÇÁ æ 1 ÒÇÆÑ)

ÖæÇÈØ ÇáãÔÇÑßÉ

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