... 9 wolfram 1
... .... ... - limit by substitution
=9 (1+2)(2/6) =1
w ( ) ... w
= 1
.... e ...... transcendental numbers ...limit by substitution
...........
\ ... ... ...... 2014
... 9 wolfram 1 62(2+1) 2 3 ( (2 (2+1) 6(2(2+1))
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: 1 (0 1 )
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