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  1. Top | #1

    Aug 2015
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    Lightbulb


    prove:
    1- If y is periodic then f(y) is periodic
    2- (f^[n] o g)(x) =(g^[n] o f)(x)

  2. Top | #2

    Feb 2014
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    :

    1) let y =g(x)is a periodic function which period=p
    Then
    g(x+np)=g(x)

    f(g(x))=f(g(x+np)

    Thenfog(x)=fog(x+np)

    So fog is periodic function

    2) fog=gof is not true always
    So the answer of the question is not true

  3. Top | #3

    Feb 2014
    18677
    ( )
    0.66
    2,919
    Thanked: 3603

    :

    1) let y =g(x)is a periodic function which period=p
    Then
    g(x+np)=g(x)

    f(g(x))=f(g(x+np)

    Thenfog(x)=fog(x+np)

    So fog is periodic function

    2) fog=gof is not true always
    So the answer of the question is not true

  4. Top | #4

    Aug 2015
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    :

    (g(x+np)=g(x

  5. Top | #5

    Feb 2014
    18677
    ( )
    0.66
    2,919
    Thanked: 3603

    :


  6. Top | #6

    Aug 2015
    20633
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    Thanked: 0

    :

    2

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